WebNov 20, 2024 · I am getting a syntax error at line 17 : unexpected token `else' declare -i A echo "enter any numeric value" read value if [$value > 0]; if [ [ "$value" =~ ^ [0-9]+$ ]]; then A=$value else if ! [ [$value =~ ^ [0-9]+$ ] $value !=0];then A=$ [RANDOM%20+1] fi fi else A=$ ( (RANDOM%25+16)) fi echo"the value of A is $A" bash syntax Share Web[size=small] 股票行情数据 服务(支持香港、深圳、上海基金、债券和股票;支持多股票同时查询) Endpoint: http://webservice ...
syntax error near unexpected token `else
WebJul 4, 2024 · 这是16年5月份编辑的一份比较杂乱适合自己观看的学习记录文档,今天18年5月份再次想写文章,发现简书还为我保存起的... Websyntax error near unexpected token `else' シェルスクリプト echo "please enter username" read user_name echo "please enter password" read -s pass echo ${ORACLE_SID} SID=${ORACLE_SID} if ["$ {ORACLE_SID}" != 'Test'] then sqlplus -s -l $USER_NAME/$PASS@$SID < fbi southern district of texas
line 98: syntax error near unexpected token `else
WebOct 23, 2024 · 前几天重装了mysql,装好之后navicat一直正常可以对mysql进行操作,但是今天要使用命令行进行操作时遇到-bash: mysql: command not found的问题。总结一下解决办法: 这个问题的出现是两个原因 1 .bash_profile中path路径不正确,这里面的路径是你当前登录的用户去执行mysql的路径,你可以直接把这个path设置为 ... WebApr 25, 2014 · I use vi editor. #!/bin/bash -x age=10; if (age -lt 13) echo "$age" else echo "xx". Any information is highly appreciable. The syntax is broken. if [ $age -lt 13 ]; then instead … Webbash: syntax error near unexpected token ` (' However, sudo -su db2inst1 id gives me correct output. So it must be something about the () If I try sudo -su db2inst1 /opt/ibm/db2/V9.7/bin/db2 force application \ (1995\) I get frightland jobs